Q. If the uncertainty in the position of an electron is $10^{- 10}$m, then the value of uncertainty in its momentum (in kg-$ms^{- 1}$) will be
A) $3.33 \times 10^{- 24}$
B) $1.03 \times 10^{- 24}$
C) $6.6 \times 10^{- 24}$
D) $6.6 \times 10^{- 24}$
Explanation
(b) $\Delta p = \frac{\hslash}{\Delta x} = \frac{1.034 \times 10^{- 34}}{10^{- 10}}$
$= 1.034 \times 10^{- 24}\ kg - ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.