Q. Photons of $5.5\ eV$ energy falls on the surface of the metal emitting photoelectrons of maximum kinetic energy $4.0\ eV.$ The stopping voltage required for these electrons are
A) $5.5\ V$
B) $1.5\ V$
C) $9.5\ V$
D) $4.0\ V$
Explanation
(d) $K_{\max} = eV_{0} \Rightarrow eV_{0} = 4eV \Rightarrow V_{0} = 4V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.