Q. A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is $10.2\ eV.$ After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of $15\ eV.$ What will be observed by the detector?
A) 2 photons of energy $10.2\ eV$
B) 2 photons of energy of $1.4\ eV$
C) One photon of energy $10.2\ eV$ and an electron of energy $1.4\ eV$
D) One photon of energy $10.2\ eV$ and another photon of $1.4\ eV$
Explanation
(c) Due to $10.2\ eV$ photon one photon of energy $10.2\ eV$ will be detected.
Due to $15\ eV$ photon the electron will come out of the atom with energy $(15 - 13.6) = 1.4\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.