Q. What is the momentum of a photon having frequency $1.5 \times 10^{13}Hz$
A) $3.3 \times 10^{- 29}kg\ m/s$
B) $3.3 \times 10^{- 34}kg\ m/s$
C) $6.6 \times 10^{- 34}kg\ m/s$
D) $6.6 \times 10^{- 30}kg\ m/s$
Explanation
(a) $p = \frac{hv}{c} = \frac{6.6 \times 10^{- 34} \times 1.5 \times 10^{13}}{3 \times 10^{8}} = 3.3 \times 10^{- 29}kg - m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.