Q. The uncertainty in the position of a particle is equal to the de-Broglie wavelength. The uncertainty in its momentum will be
A) $h/\lambda$
B) $2h/3\lambda$
C) $\lambda/h$
D) $3\lambda/2h$
Explanation
(a) $\delta p = \frac{\hslash}{\mathrm{\Delta}x} = \frac{\hslash}{\lambda}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.