(c) ${\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda}_{0} = \frac{hc}{W_{0}} = \frac{12400}{4}$ = $3100\mathring{\mathrm{A}} = \ 310\ nm$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.