(b) Intensity of light source is
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ I \propto \frac{1}{d^{2}}$
When distance is doubled, intensity becomes one-fourth.
As number of photoelectrons $\propto$ intensity, so number of photoelectrons is quarter of the initial number.