(a) $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ F = qE$
or$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ma = eE$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a = \frac{qE}{m}$
or$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a = \frac{eE}{m}$ in the opposite direction of the field.