An electron of mass $m$ and charge $q$ is accelerated from rest in a uniform electric field of strength $E$. The velocity acquired by it as it travels a distance $l$ is

Question

Dr. Abubacker · Accepted Answer

(a) Here, $u = 0,\ a = qE/m$; $s = l$ and $v = ?$
As $v^{2} = u^{2} + 2as;so\ v^{2} = 0 + 2\frac{q\ E\ l}{m}$
or $v = \frac{\sqrt{2qEl}}{m}$

Q. An electron of mass $m$ and charge $q$ is accelerated from rest in a uniform electric field of strength $E$. The velocity acquired by it as it travels a distance $l$ is

Explanation

Reviewed by Dr. Abubacker

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