The wavelength of most energetic $X$-rays emitted when a metal target is bombarded by $40KeV$ electrons, is approximately $(h = 6.62 imes 10^{- 34}J$-$sec,\ 1\ eV = 1.6 imes 10^{- 19}J;c = 3 imes 10^{8}m/s)$

Question

The wavelength of most energetic $X$-rays emitted when a metal target is bombarded by $40KeV$ electrons, is approximately $(h = 6.62 	imes 10^{- 34}J$-$sec,\ 1\ eV = 1.6 	imes 10^{- 19}J;c = 3 	imes 10^{8}m/s)$

Dr. Abubacker · Accepted Answer

(d) $\lambda = \frac{12375}{(40 	imes 10^{3})} = 0.309\mathring{\mathrm{A}} \approx 0.31\mathring{\mathrm{A}}$

Q. The wavelength of most energetic $X$-rays emitted when a metal target is bombarded by $40KeV$ electrons, is approximately $(h = 6.62 \times 10^{- 34}J$-$sec,\ 1\ eV = 1.6 \times 10^{- 19}J;c = 3 \times 10^{8}m/s)$

Explanation

Reviewed by Dr. Abubacker

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