Q. If the energy of photons corresponding to the wavelength of 6000$\mathring{\mathrm{A}}$ is $3.2 \times 10^{- 19}$ J, the photon energy for a wavelength of 4000$\mathring{\mathrm{A}}$ will be
A) $1.11 \times 10^{- 19}\ J$
B) $2.22 \times 10^{- 19}\ J$
C) $4.40 \times 10^{- 19}\ J$
D) $4.80 \times 10^{- 19}$ $J$
Explanation
(d) $E = hc/\lambda$ or $E \propto l/\lambda$; so $E_{2} = E_{1} \times \lambda_{1}/\lambda_{2}$
$= 3.2 \times 10^{- 19} \times 6000/4000 = 4.8 \times 10^{- 19}$ J
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.