Q. Light of frequency $4v_{0}$ is incident on the metal of the threshold frequency $v_{0}.$ The maximum kinetic energy of the emitted photoelectrons is
A) $3hv_{0}$
B) $2hv_{0}$
C) $\frac{3}{2}hv_{0}$
D) $\frac{1}{2}hv_{0}$
Explanation
(a) $E = hv_{0} + K_{\max} \Rightarrow h\left( 4v_{0} \right) = hv_{0} + K_{\max} \Rightarrow K_{\max} = 3hv_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.