In $X$-ray tube when the accelerating voltage $V$ is halved, the difference between the wavelength of $K_{\alpha}$ line and minimum wavelength of continuous $X$-ray spectrum

Question

Dr. Abubacker · Accepted Answer

(d) $\mathrm{\Delta}\lambda = \lambda_{K_{\alpha}} - \lambda_{\min}$ When $V$ is halved $\lambda_{\min}$ becomes two time but $\lambda_{K_{\alpha}}$ remains the same.
$	herefore\mathrm{\Delta}\lambda^{'} = \lambda_{K_{\alpha}} - 2\lambda_{\min} = 2(\Delta\lambda) - \lambda_{K_{\alpha}}$
$	herefore\mathrm{\Delta}\lambda^{'} < 2(\Delta\lambda)$

Q. In $X$-ray tube when the accelerating voltage $V$ is halved, the difference between the wavelength of $K_{\alpha}$ line and minimum wavelength of continuous $X$-ray spectrum

Explanation

Reviewed by Dr. Abubacker

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