Q. X-ray are diffracted from a crystal of lattice plane spacing $2\mathring{\mathrm{A}}$. The maximum wavelength that can be diffracted is
A) $\ 1\mathring{\mathrm{A}}$
B) $2\ \mathring{\mathrm{A}}$
C) $2.5\mathring{\mathrm{A}}$
D) $4\mathring{\mathrm{A}}$
Explanation
(d) Using Bragg’s formula,
$2d\sin\theta = \gimel$
Given, $\ d =$ 2A
For maximum wavelength
$\gimel$$_{max}$ = 2d = 2$\times 2$A=4A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.