In producing $X$-rays a beam of electrons accelerated by a potential difference $V$ is made to strike a metal target. For what value of $V,\ X$-rays will have the lowest wavelength of $0.3094\ \mathring{\mathrm{A}}$

Question

Dr. Abubacker · Accepted Answer

(d) From the formula
$V = \frac{12375}{\lambda_{\min}} = \frac{12375}{0.3094} = 39.99\ kV = 40\ kV$

Q. In producing $X$-rays a beam of electrons accelerated by a potential difference $V$ is made to strike a metal target. For what value of $V,\ X$-rays will have the lowest wavelength of $0.3094\ \mathring{\mathrm{A}}$

Explanation

Reviewed by Dr. Abubacker

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