(c) Specific charge on proton =$\left( \frac{e}{m} \right)_{p}$
$= 9.6 \times 10^{7}{Ckg}^{- 1}$ specific charge on $\propto$-particle,
$\left( \frac{q}{m} \right)_{\propto} = \frac{2e}{4m} = \frac{1}{2}\left( \frac{e}{m} \right)_{p} = \frac{1}{2} \times 9.6 \times 10^{7}$
$= \ 4.8 \times 10^{7}\ {Ckg}^{- 1}$