Q. The threshold wavelength for photoelectric effect of a metal is $6500\ \mathring{\mathrm{A}}.$ The work function of the metal is approximately
A) $2\ eV$
B) $1\ eV$
C) $0.1\ eV$
D) $3\ eV$
Explanation
(a) $W_{0(eV)} = \frac{12375}{6500\mathring{\mathrm{A}}} = 1.9eV = 2eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.