Q. The ionization energy of hydrogen atom is 13.6eV. Following Bohr’s theory, the energy corresponding to a transition between 3rd and 4th orbit is
A) 3.40 eV
B) 1.51 eV
C) 0.85 eV
D) 0.66 eV
Explanation
(d) $E = E_{4} - E_{3}$
$= - \frac{13.6}{4^{2}}—\left( - \frac{13.6}{3^{2}} \right) = - 0.85 + 1.51$
$= 0.66\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.