Q. The energy of an electron in $n$th orbit of the hydrogen atom is given by $E_{n} = \frac{- 13.6}{n^{2}}eV$ The energy required to raise an electron from the first orbit to the second orbit will be

A) 10.2 eV
B) 12.1 eV
C) 13.6 eV
D) 3.4 eV
Explanation

(a) $E = E_{2} - E_{1} = - \frac{13.6}{2^{2}}—\left( - \frac{13.6}{1^{2}} \right) = 10.2\ eV$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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