Q. The ratio of minimum wavelength of Lyman and Balmer series will be
A) 10
B) 5
C) 0.25
D) 1.25
Explanation
(c) $\lambda\ \propto \ n^{2}$
$\therefore\ \ \ \ \ \ \ \ \frac{\lambda_{Lyman}}{\lambda_{Balmer}}$ $= \left( \frac{1}{2} \right)^{2} = \frac{1}{4}$ $=$0.25
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.