Q. The figure indicates the energy levels of a certain atom. When the system moves from $2E$ level to$E$, a photon of wavelength $\lambda$ is emitted. The wavelength of photon produced during its transition from $\frac{4E}{3}$level to $E$ is
A) $\frac{\lambda}{3}$
B) $\frac{3\lambda}{4}$
C) $\frac{4\lambda}{3}$
D) $3\lambda$
Explanation
(d) In the first case, energy emitted,
$E_{1} = 2E - E = E$
In the second case, energy emitted
$E_{2} = \frac{4E}{3} - E = \frac{E}{3}$
As $E_{3}$ is $\frac{1}{3}$ rd, $\lambda_{2}$must be 3 times, $ie,3\lambda$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.