Q. Two energy lavels of an electron in an atom are separated by 2.3 $eV$. The frequency of radiation emitted when the electrons go from higher to lower level is
A) $6.95\ \times \ 10^{14}\ Hz$
B) $3.68\ \times \ 10^{15}\ Hz$
C) $5.6\ \times \ 10^{14}\ Hz$
D) $9.11 \times \ 10^{15}\ Hz$
Explanation
(c) Given, $E_{2} - E_{1} = \ 2.3\ eV$
Or v= $\frac{E2 - E1}{h} = \frac{2.3\ \times \ 1.6 \times 10^{- 19}}{6.6\ \times 10^{- 34}}$
= $0.55\ \times \ 10^{15}$
= $5.5\ \times \ 10^{14}\ Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.