Q. For an electron in the second orbit of Bohr’s hydrogen atom, the moment of linear momentum is
A) $n\pi$
B) 2$\pi h$
C) $\frac{2h}{\pi}$
D) $\frac{h}{\pi}$
Explanation
(d) The moment of linear momentum is angular momentum
$\ \ \ \ \ \ \ \ \ \ \ L\ = \ mvr\ $= $\frac{nh}{2\pi}$
Here, $n$=2
$\therefore\ \ \ \ \ \ L = \frac{2h}{2\pi} = \ \frac{h}{\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.