If the binding energy of the electron in a hydrogen atom is 13.6 $eV$, the energy required to remove the electron from the first excited state of $Li^{2 +}$ is

Question

Dr. Abubacker · Accepted Answer

(a) $E\  = \  - \ Z^{2}\frac{13.6}{n^{2}}eV$
For first excited state,
$\ \ \ \ \ \ \ \ \ \ E_{2}\  = \  - 3^{2} 	imes \frac{13.6}{4}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  = \  - 30.6\ eV$
Ionisation energy for first excited state of $Li^{2 +}$ is 30.6 eV.

Q. If the binding energy of the electron in a hydrogen atom is 13.6 $eV$, the energy required to remove the electron from the first excited state of $Li^{2 +}$ is

Explanation

Reviewed by Dr. Abubacker

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