Q. The series limit wavelength of the Lyman series for the hydrogen atom is given by
A) $1/R$
B) $4/R$
C) $9/R$
D) $16/R$
Explanation
(a) For Lyman series, $n_{1} = 1,\ n_{2} = \infty$
$\frac{1}{\lambda} = R\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right) = R\left( \frac{1}{1^{2}} - \frac{1}{\infty} \right) = R$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.