(a) $\ \ \ \ \ \ \ U\ = eV\ = eV_{0}\ln\left( \frac{r}{r_{0}} \right)$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |F| = \ \left| - \frac{dU}{dr} \right| = \frac{{eV}_{0}}{r}$
This force will provide the necessary centripetal force. Hence
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{{mv}^{2}}{r} = \frac{{eV}_{0}}{r}$
or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v$= $\sqrt{\frac{{eV}_{0}}{m}}$ ….(i)
Moreover
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ mvr\ = \frac{nh}{2\pi}$ …..(ii)
Dividing Eq. (ii) by Eq. (i), we have
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ mr = \left( \frac{nh}{2\pi} \right)\sqrt{\frac{\ m}{{eV}_{0}}}$
Or $r_{n} \propto n$