Q. In a hypothetical bohr hydrogen atom, the mass of the electron is doubled. The energy $E_{o}$and energy $r_{o}$ of the first orbit will be ($a_{o}$ is the Bohr radius)
A) $E_{o} = - 27.2eV;r_{o} = a_{o}/2$
B) $E_{o} = - 27.2eV;r_{o} = a_{o}$
C) $E_{o} = - 13.6eV;r_{o} = a_{o}/2$
D) $E_{o} = - 13.6eV;r_{o} = a_{o}$
Explanation
(a) As $r \propto \frac{1}{m}$
$\therefore r_{0} = \frac{1}{2}a_{0}$
As $E \propto m$
$\therefore E_{0} = 2( - 13.6) = - 27.2\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.