Q. Which of the following atoms has the lowest ionization potential?

A) $_{7}^{14}N$
B) $_{55}^{133}{Cs}$
C) $_{18}^{40}{Ar}$
D) $_{8}^{16}O$
Explanation

(b) As $_{55}$Cs$^{133}$ has larger size among the four atoms given, thus, electrons present in the outermost orbit will be away from the nucleus and the electrostatic force experienced by electrons due to nucleus will be minimum. Therefore, the energy required to liberate electrons from outer orbit will be minimum in case of$_{55}$Cs$^{133}$.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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