Given that in a hydrogen atom, the energy of $n$th orbit $E_{n} = - \frac{13.6}{n^{2}}eV$. The amount of energy required to send electron from first orbit to second orbit is

Question

Dr. Abubacker · Accepted Answer

(a) $E = E_{2} - E_{1} = - \frac{13.6}{2^{2}} - \left( —\frac{13.6}{1^{2}} \right) = 10.2\ eV$

Q. Given that in a hydrogen atom, the energy of $n$th orbit $E_{n} = - \frac{13.6}{n^{2}}eV$. The amount of energy required to send electron from first orbit to second orbit is

Explanation

Reviewed by Dr. Abubacker

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