Q. If the electron is a hydrogen atom jumps from an orbit with level $n_{1} = 3$ to an orbit with level $n_{1} = 2,$ the emitted radiation has a wavelength given by
A) $\lambda = \frac{36}{5R}$
B) $\lambda = \frac{5R}{36}$
C) $\lambda = \frac{6}{R}$
D) $\lambda = \frac{R}{6}$
Explanation
(a) Wavelength emitted $(\lambda)$is given by
$\frac{1}{\lambda} = R\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right) = R\left( \frac{1}{2^{2}} - \frac{1}{3^{2}} \right) = \frac{5R}{36}$
$\lambda = \frac{36}{5R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.