Q. The ratio of kinetic energy and the total energy of the electron in the $n$th quantum state of Bohr’s atomic model of hydrogen atom is
A) $- 2$
B) $- 1$
C) $+ 2$
D) $+ 1$
Explanation
(b) The Kinetic energy of the electron in the $n$th state
$\ \ \ \ \ \ \ \ \ \ \ \ \ K = \frac{{mZ}^{2}e^{4}}{8\varepsilon_{0}^{2}h^{2}n^{2}}$
The total energy of the electron in the $n$th state
$\ \ \ \ \ \ \ \ \ \ \ \ \ T\ = \ - \frac{{mZ}^{2}e^{4}}{8\varepsilon_{0}^{2}h^{2}n^{2}}$
$\therefore\ \ \ \ \ \ \ \ \ \frac{K}{T} = \ - 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.