Q. If series limit of Balmer series is $6400\ \mathring{\mathrm{A}}$,$\ $then series limit of Paschen series will be

A) $6400\ \mathring{\mathrm{A}}$
B) $18680\ \mathring{\mathrm{A}}$
C) $14400\ \mathring{\mathrm{A}}$
D) $2400\ \mathring{\mathrm{A}}$
Explanation

(c) Series limit of Balmer series is given by
$\frac{1}{\lambda_{\min}} = R\left( \frac{1}{2^{2}} - \frac{1}{\infty} \right) = \frac{R}{4}$
$R = \frac{4}{\lambda_{\min}} = \frac{4}{6400} = \frac{1}{1600}\mathring{\mathrm{A}}^{- 1}$
Series limit of Paschen series would be
$\frac{1}{\lambda_{\min}} = R\left( \frac{1}{3^{3}} - \frac{1}{\infty} \right) = \frac{R}{9}$
$\lambda_{\min} = \frac{9}{R} = \frac{9}{1/1600} = 14400\mathring{\mathrm{A}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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