(d) $E\ = \ E_{1}/n^{2}$
Energy used for excitation is 12.75 eV
$ie,$ $( - 13.6\ + 12.75)\ eV\ = \ - \ 0.85\ eV$
Energy levels of H-atom
The photon of energy 12.75$\ eV$ can excite the fourth level of H-atom
Therefore, six lines will be emitted.
$\left( n\frac{(n - 1)}{2}\ lines \right).$