Q. When an electron jumps from the orbit $n = 2$ to $n = 4$,then wavelength of the radiations absorbed will be ($R$ is Rydberg’s constant)

A) $\frac{3R}{16}$
B) $\frac{5R}{16}$
C) $\frac{16}{5R}$
D) $\frac{16}{3R}$
Explanation

(d) $\frac{1}{\lambda}$= $R\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack$
$n_{1}$=2, $n_{2}$=4
$\frac{1}{\lambda} =$ $R\left\lbrack \frac{1}{4} - \frac{1}{16} \right\rbrack$
$= R\left\lbrack \frac{4 - 1}{16} \right\rbrack$ $=$ $\frac{3\ R}{16}$
$\lambda = \frac{16}{3R}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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