Q. Wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
A) $6563\ \mathring{\mathrm{A}}$
B) $4102\ \ \mathring{\mathrm{A}}$
C) $4861\ \mathring{\mathrm{A}}$
D) $1215\ \ \mathring{\mathrm{A}}$
Explanation
(d) $\ \ \ \ \ \ \ \ \frac{1}{\lambda} = R\left( \frac{1}{1^{2}} - \frac{1}{2^{2}} \right)$
$\Rightarrow \ \ \ \ \frac{1}{\lambda} = 1.097\ \times 10^{7} \times \frac{3}{4}$
$\therefore\ \ \ \ \lambda\ = 1.215\ \times 10^{- 7}m\ = \ 1215\ \mathring{\mathrm{A}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.