Q. Which of the following transition gives the photon of minimum frequency?
A) $n$=2 to $\ n$=1
B) $n$ =3 to $\ n$=1
C) $n$ =3 to $\ n$=2
D) $n$ =4 to $\ n$=3
Explanation
(d) [image:12_image4.emf]
$E_{1}$ = $- 13.6\ –( - 3.4)\ = \ - 10.2\ eV$
$E_{2}\ = \ - \ 13.6\ –\ (\ - \ 1.51)\ = \ - 12.09\ eV$
$E_{3}\ = \ - \ 3.4\ –\ (\ - 1.5) = \ - \ 1.89\ eV$
$E_{4}\ = \ - \ 1.51\ –\ (\ - \ 0.85) = - \ 0.66\ eV$
$E_{4}\ \ $is least $ie,$ frequency is lowest.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.