Q. The ratio of the energies of the hydrogen atom in its first to second excited states is
A) 9/4
B) 4/1
C) 8/1
D) 1/8
Explanation
(a) 1st excited state corresponds to $n = 2$
2nd excited state corresponds to $n = 3$
$\frac{E_{1}}{E_{2}} = \frac{n_{3}^{2}}{n_{2}^{2}} = \frac{3^{2}}{2^{2}} = \frac{9}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.