Q. Let the PE of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be
A) 27.2 eV
B) 23.8 eV
C) 12.6 eV
D) 10.2 eV
Explanation
(d) In ground state TE=$- 13.6$ eV
In first excited state, TE=$- 3.4\ eV,\ ie,$
10.2 eV above the ground state.
If ground state energy is taken as zero, the total energy in
First excited state $= 10.2\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.