Q. $1\ g$ of hydrogen is converted into $0.993\ g$ of helium in a thermonuclear reaction. The energy released is
A) $63 \times 10^{7}J$
B) $63 \times 10^{10}J$
C) $63 \times 10^{14}J$
D) $63 \times 10^{20}J$
Explanation
(b) $\mathrm{\Delta}m = 1 - 0.993 = 0.007\ gm$
$\therefore E = (\mathrm{\Delta}m)c^{2} = \left( 0.007 \times 10^{- 3} \right)\left( 3 \times 10^{8} \right)^{2} = 63 \times 10^{10}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.