If the binding energy per nucleon in $\ _{3}Li^{7}and\ \ _{2}He^{4}$nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction $\ _{3}Li + p \rightarrow 2_{2}He\ ^{4}$ is

Question

Dr. Abubacker · Accepted Answer

(d) Applying principle of energy conservation.
Energy of proton=total BE of $2\ \alpha -$energy of $Li^{7}$
$= 8 	imes 7.06 	imes 7 	imes 5.6$
$= 56.48 - 39.2 = 17.28\ MeV$

Q. If the binding energy per nucleon in $\ _{3}Li^{7}and\ \ _{2}He^{4}$nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction $\ _{3}Li + p \rightarrow 2_{2}He\ ^{4}$ is

Explanation

Reviewed by Dr. Abubacker

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