Q. The energy released in the fission of 1Kg of $\ _{92}U^{235}$ is (energy per fission =200 MeV)
A) $5.1 \times \ 10^{26}eV$
B) $5.1\ \times \ 10^{26}\ J$
C) $8.2\ \times 10^{13}\ J$
D) $8.2\ \times \ 10^{13}\ MeV$
Explanation
(c) Energy released from 1 kg of uranium
$= \frac{200\ \times 10^{6} \times 1.6 \times 10^{- 19} \times \ 6.023\ \times 10^{26}}{235}$
$\ = \ 8.2\ \times \ 10^{13}\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.