Q. Ionization energy of hydrogen is $13.6\ eV$. If $h = 6.6 \times 10^{- 34}J - s$, the value of $R$ will be of the order of
A) $10^{10}m^{- 1}$
B) $10^{7}m^{- 1}$
C) $10^{4}m^{- 1}$
D) $10^{- 7}m^{- 1}$
Explanation
(b) $E = - Rch \Rightarrow R = - \frac{E}{ch} = \frac{13.6 \times 1.6 \times 10^{- 19}}{3 \times 10^{8} \times 6.6 \times 10^{- 34}}$
$= 1.098 \times 10^{7}per\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.