(b) Nuclear radius is proportional to $\ A^{1/3}$ $\ \ \ \ \ \ \ \ \ \ R = R_{0}A^{1/3}$ $\therefore\ \ \ \ \ \ \ \frac{R_{1}}{R_{2}}\ = \left\lbrack \frac{7}{56} \right\rbrack^{1/3} = \frac{1}{2}$
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Ph.D. in Physics with 19+ years of teaching experience.