Q. An ionic atom equivalent to hydrogen atom has wavelength equal to 1/4 of the wavelength of hydrogen lines. The ion will be
A) $He^{+}$
B) $Li^{+ +}$
C) $Ne^{9 +}$
D) $Na^{10 +}$
Explanation
(a) $\overline{v} \propto \frac{1}{\lambda} \propto Z^{2} \Rightarrow \lambda Z^{2} =$ constant $\Rightarrow \lambda = \frac{\lambda}{4}Z^{2} \Rightarrow Z = 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.