Q. The following diagram indicates the energy levels of a certain atom when the system moves from $2E$ level to $E$, emitting a photon of wavelength $\lambda$. The wavelength of photon produced during its transition from $\frac{4E}{3}$ level to $E$ is
A) $\lambda/3$
B) $3\lambda/4$
C) $4\lambda/3$
D) $3\lambda$
Explanation
(d) $2E - E = \frac{hc}{\lambda} \Rightarrow E = \frac{hc}{\lambda}$
$\frac{4E}{3} - E = \frac{hc}{\lambda^{'}} \Rightarrow \frac{E}{3} = \frac{hc}{\lambda^{'}}\ \therefore\frac{\lambda^{'}}{\lambda} = 3 \Rightarrow \lambda^{'} = 3\lambda$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.