Two radioactive sources $A$ and $B$ of half lives 1h and 2h respectively initially contain the same number of radioactive atoms. At the end of two hours, their rates of disintegration are in the ratio of

Question

Dr. Abubacker · Accepted Answer

(c) Rate of disintegration $\propto$ Number of atoms left
In case of source $A,\ \ \frac{N}{N_{0}} = \left( \frac{1}{2} ight)^{2} = \frac{1}{4}$
In case of source $B,\ \ \frac{N}{N_{0}} = \left( \frac{1}{2} ight)^{1} = \frac{1}{2}$
$	herefore\ \frac{R_{A}}{R_{B}} = \frac{N_{0}/4}{N_{0}/2} = \frac{1}{2}$

Q. Two radioactive sources $A$ and $B$ of half lives 1h and 2h respectively initially contain the same number of radioactive atoms. At the end of two hours, their rates of disintegration are in the ratio of

Explanation

Reviewed by Dr. Abubacker

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