Q. According to Bohr’s model, the radius of the second orbit of helium atom is
A) $0.53\ \mathring{\mathrm{A}}$
B) $1.06\ \mathring{\mathrm{A}}$
C) $2.12\ \mathring{\mathrm{A}}$
D) $0.265\ \mathring{\mathrm{A}}$
Explanation
(b) $r = \frac{n^{2}}{Z}\left( r_{0} \right); \Rightarrow r_{(n = 2)} = \frac{(2)^{2}}{2} \times 0.53 = 1.06\ \mathring{\mathrm{A}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.