Q. Complete the equation for the following fission process $\ _{92}U^{235} + \ _{0}n^{1} \rightarrow \ _{38}Sr^{90} + \ldots$
A) $\ _{54}{Xe}^{143} + {3\ }_{0}n^{1}$
B) $\ _{54}{Xe}^{145}$
C) $\ _{57}{Xe}^{142}$
D) $\ _{54}{Xe}^{142} + \ _{0}n^{1}$
Explanation
(a) $\ _{92}U^{235} + \ _{0}n^{1} \rightarrow \ _{38}Sr^{90} + \ _{54}{Xe}^{143} + {3\ }_{0}n^{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.