Q. If the distance between nuclei is $2 \times 10^{- 13}$cm, the density of nuclear material is

A) $3.21 \times 10^{- 12}kgm^{- 3}$
B) $1.6 \times 10^{- 3}kgm^{- 3}$
C) $2 \times 10^{9}kgm^{- 3}$
D) $4 \times 10^{17}kgm^{- 3}$
Explanation

(d) Density of nuclear material=mass/volume.
$\frac{10^{- 27}}{\frac{4}{3}\pi r^{3}} = \frac{3 \times 10^{- 27}}{4\pi\left( 2 \times 10^{- 15} \right)^{3}} = 10^{17}kgm^{- 3}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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