Q. In a radioactive decay. The half-life of radioactive substance is T$_{1/2}$ = 69.3s. The decay constant is

A) $1.5\ s^{- 1}$
B) $2.21\ s^{- 1}$
C) $0.01\ s^{- 1}$
D) $3.01\ s^{- 1}$
Explanation

(c) Decay constant $\lambda = \frac{0.693}{T_{1/2}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \ \frac{0.693}{69.3}\ = 0.01\ s^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Nuclei MCQs